Factoring
Week Two Discussion Questions
How do you factor the difference of two squares?
This expression is called a difference of two squares:
The factors of a2 - b2 are:
(a + b) and (a -- b)
How do you factor the perfect square trinomial?
Both x2 and 9 are perfect squares.
Because subtraction is occurring between these squares, this expression is the difference of two squares.
x2 = x * x
The factors are (x + 3) and (x - 3).
(x + 3) (x - 3) or (x - 3) (x + 3)
How do you factor the sum and difference of two cubes?
The sum of two cubes is factored like this:
a3 + b3 = (a + b)(a2 -- ab + b2)
The difference of two cubes is factored like this:
= (a -- b)(a2 + ab + b2)
Which of these three makes the most sense to you? Explain why.
Factoring the perfect square trinomial makes the most sense to me because the calculations seem intuitive -- nothing unexpected or complex happens. Either a square exists or it does not; factoring is a relatively simple matter for squares.
Week Three Discussion Questions
Do all rational equations have a single solution? Why is that so?
Not all rational equations have a single solution.
Given, for example:
f (x) = (x2 + 2x + 1)/(x^4 + 2)
Then, x can be any real value, which will result in many possible solutions.
What constitutes a rational expression? How would you explain this concept to someone unfamiliar with it?
A rational express is the ratio of two polynomials. It is considered "rational" because one number is divided by another number:
x2 + 5 / x + 2
This operation is just like what occurs in a ratio. But note that the polynomial that you are dividing by cannot be zero.
Week Four Discussion Questions
Write a word problem involving a quadratic function. How would you explain the steps in finding the solution to someone not in this class?
Given the area of a rectangle is 560 square inches. The length is 3 more than twice the width. Find the length and the width.
L = length
W = width.
Since the length is 3 more than twice the width, then:
L = 2W + 3
The area of the rectangle is 560, so:
LW = 560
Use L = 2W +3 to solve for W:
LW = 560
(2W = 3)W = 560
2W2 + 3W = 560 (Subtract 560 from each side of the equation)
2W2 + 3W -- 560 = 0
Use the Quadratic Formula:
W = -3+/- ? 9 -- 4 (2) (-560) / 2.2 =
W = -3+/- ?4489 / 4 = -3+/- 67 / 4 = -70 / 4 Or 64 / 4 = 16
But since the width can't be negative, then:
L = 2 * 16 + 3 = 35
What is the relationship between exponents and logarithms? How would you distinguish between the two, using both a graph and a sequence?
Just like subtraction will "undo" addition, logarithms are the opposite of exponentials, and can "undo" them. Logarithms are the inverse of exponentials. Logarithms answer the question: "Which exponential produced this (the problem being solved) equation?"
For example y = bx is the equivalent of logb (y) = x
Sequentially, whatever had been the argument of the log can be the "equals" and what ever had been the "equals" can be the exponent in the exponential.
As X gets larger on the graph, the function value of f (x) increases dramatically. So the function is called an exponential function.
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