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In each measurement, and the average value of D. from its three resulting values:
d" (in mm) l" (in mm)
D=(d/l)*150,000,000 km
Average:
don't average data)
In the table above, in the first measurement taken at 3:10pm, the value of d is 55.7 mm, while l is 5,998 mm. Substituting these values to the derived formula for D, which is D = (d/l) L, we get D = (55.7mm/5,998mm)(150,000,000km), or D = 1,392,964.32km. For the second measurement taken at 3:20pm, the value of d is 56.25mm, while l is 6,000mm. By substitution, D = (56.25mm/6,000mm)(150,000,000km), or D = 1,406,250km. For the last measurement taken at 3:30pm, the value of d is 56.6mm, while l is 6,003mm. By substitution again, we get D = (56.6mm/6,003mm)(150,000,000km), or D = 1,414,292.85km. The average value of D. can be taken by adding the values of D. from the three measurements in the experiment, and then dividing its result by three. In mathematical terms it translates: D = (D1 + D2 + D3)/3. By substituting the values of D. from the table above to this formula, we have D = (1,392,964.32km + 1,406,250km + 1,414,292.85km)/3, or, equivalently, D = 1,404,502.39km. Therefore, the diameter of the sun is approximately 1,404,502.39km.
In this experiment, I have learned how...
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