Graphing Inequalities Research Paper

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The numbers are converted into a point, and that point is used as a test point to see if they fall within the shaded area of the graph. If the test point is in shaded area, the combination can fit. If the test point is outside of the shaded area, then the combination will not work. This can also be determined by plugging the numbers into the equation for the linear equality, which can provide more precise answers than a quick visual assessment from a graph, particularly if the point is close to the line created by the linear inequality. The first question asked is: will the truck hold 71 refrigerators and 118 TVs? Those numbers are plugged into the equation y = ? -3x + 330. The number sentence resulting is: 118 ? -3(71) + 330? Simplified, that sentence reads 118 ? 117. Clearly that is false. Therefore, the truck cannot hold that combination of TVs and refrigerators. Instead, if there are 71 refrigerators, the truck can hold up to 117 TVs, but not 118.

Next, the text asks whether the truck will hold 51 refrigerators and 176 TVs? The resulting number sentence becomes 176 ? -3(51) + 330. Simplified, that reads 176 ? 177. This is a true...

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Therefore, the truck will hold that combination of TVs and refrigerators.
The next question asks how many TVs it could buy if the Buy More will purchase a maximum of 60 refrigerators. The order will contain between 0 and 60 refrigerators. The maximum number of TVs would be based on 0 refrigerators in the shipment and would be 330, as determined in the first paragraph. The maximum number of TVs that would ship if Buy More purchased its stated maximum number of refrigerators for this order would be based on using 60 refrigerators. The answer for that is 150 TVs. This would not change the graph of the linear inequality, but it would cause a line, parallel to the y-axis to drop down from the point where x-60 to indicate that no answers beyond that line where within the solution set for the new conditions.

If the Burbank Buy More orders a minimum of 200 TVs, the maximum number of refrigerators is not figured by looking at a zero order, but by setting 200 as the new minimum. The resulting number sentence reads: 200 ? -3x + 330. Solving for x yields 43.3, but refrigerators are shipped as whole units, providing an…

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